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4.9x^2-5x-1.5=0
a = 4.9; b = -5; c = -1.5;
Δ = b2-4ac
Δ = -52-4·4.9·(-1.5)
Δ = 54.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{54.4}}{2*4.9}=\frac{5-\sqrt{54.4}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{54.4}}{2*4.9}=\frac{5+\sqrt{54.4}}{9.8} $
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